0.003x^2-0.35x+10=x

Solution for 0.003x^2-0.35x+10=x equation:

0.003x^2-0.35x+10=x

We move all terms to the left:

0.003x^2-0.35x+10-(x)=0

We add all the numbers together, and all the variables

0.003x^2-1.35x+10=0

a = 0.003; b = -1.35; c = +10;
Δ = b2-4ac
Δ = -1.352-4·0.003·10
Δ = 1.7025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.35)-\sqrt{1.7025}}{2*0.003}=\frac{1.35-\sqrt{1.7025}}{0.006}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.35)+\sqrt{1.7025}}{2*0.003}=\frac{1.35+\sqrt{1.7025}}{0.006}
$